What are the solutions to the equation p^2-14p+49=0 ?

The solutions to the equation p^2-14p+49=0 are p=7

Find the zeros of p^2-14p+49=0

The zeros of p^2-14p+49=0 are p=7

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p^{2} - 14 p + 49 = 0

p = 7

Solution steps

p^{2} - 14 p + 49 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

p_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

p = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

p = 7

The solution to the quadratic equation is:

p = 7

- 3 x^{2} - 7 x + 10 = 0

6 x^{2} - 4 x + 3 = 0

x^{2} - 2 x + 17 = 0

t, s = 5 + 3 t + 2 t^{2}

y^{2} - 63 = 0

What are the solutions to the equation p^2-14p+49=0 ?
The solutions to the equation p^2-14p+49=0 are p=7
Find the zeros of p^2-14p+49=0
The zeros of p^2-14p+49=0 are p=7