What are the solutions to the equation solvefor x,x-x^2-xy=0 ?

The solutions to the equation solvefor x,x-x^2-xy=0 are x=0,x=1-y

Find the zeros of solvefor x,x-x^2-xy=0

The zeros of solvefor x,x-x^2-xy=0 are x=0,x=1-y

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solve for

x, x - x^{2} - x y = 0

x = 0, x = 1 - y

Solution steps

x - x^{2} - x y = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + (1 - y) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 1 - y ) \pm ( 1 - y ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

Simplify

(1 - y)^{2} - 4 (- 1) \cdot 0 : - y + 1

x_{1, 2} = \frac{- ( 1 - y ) \pm ( - y + 1 )}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( 1 - y ) - y + 1}{2 ( - 1 )}, x_{2} = \frac{- ( 1 - y ) - ( - y + 1 )}{2 ( - 1 )}

x = \frac{- ( 1 - y ) - y + 1}{2 ( - 1 )} : 0

x = \frac{- ( 1 - y ) - ( - y + 1 )}{2 ( - 1 )} : 1 - y

The solutions to the quadratic equation are:

x = 0, x = 1 - y

2 x^{2} = - x - 1

- 4 y^{2} - 8 y = 0

\frac{1}{2} x^{2} + 5 x - 1 = 0

3 x^{2} - 10 x - 77 = 0

- 2 x^{2} + 4 x = 3

What are the solutions to the equation solvefor x,x-x^2-xy=0 ?
The solutions to the equation solvefor x,x-x^2-xy=0 are x=0,x=1-y
Find the zeros of solvefor x,x-x^2-xy=0
The zeros of solvefor x,x-x^2-xy=0 are x=0,x=1-y