What are the solutions to the equation -4x^2-4x+5=-7x^2 ?

The solutions to the equation -4x^2-4x+5=-7x^2 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3

Find the zeros of -4x^2-4x+5=-7x^2

The zeros of -4x^2-4x+5=-7x^2 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3

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- 4 x^{2} - 4 x + 5 = - 7 x^{2}

x = \frac{2}{3} + i \frac{11}{3}, x = \frac{2}{3} - i \frac{11}{3}

Solution steps

- 4 x^{2} - 4 x + 5 = - 7 x^{2}

Move

7 x^{2}

to the left side

3 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 5 : 211 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 11 i}{2 \cdot 3} : \frac{2}{3} + i \frac{11}{3}

x = \frac{- ( - 4 ) - 2 11 i}{2 \cdot 3} : \frac{2}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{11}{3}, x = \frac{2}{3} - i \frac{11}{3}

15 x^{2} - 20 x = 0

42 = (x + 6) (x + 4)

300 0^{2} + 400 0^{2} = x^{2}

2 x^{2} + 4 x + 96 = 0

x, 64 x^{2} - 48 x y + 9 y^{2} = 0

What are the solutions to the equation -4x^2-4x+5=-7x^2 ?
The solutions to the equation -4x^2-4x+5=-7x^2 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3
Find the zeros of -4x^2-4x+5=-7x^2
The zeros of -4x^2-4x+5=-7x^2 are x= 2/3+i(sqrt(11))/3 ,x= 2/3-i(sqrt(11))/3