What are the solutions to the equation 0=-1/16 (x-32)^2+67 ?

The solutions to the equation 0=-1/16 (x-32)^2+67 are x=4sqrt(67)+32,x=-4sqrt(67)+32

Find the zeros of 0=-1/16 (x-32)^2+67

The zeros of 0=-1/16 (x-32)^2+67 are x=4sqrt(67)+32,x=-4sqrt(67)+32

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0 = - \frac{1}{16} (x - 32)^{2} + 67

x = 467 + 32, x = - 467 + 32

Decimal Notation

x = 64.74141 \dots, x = - 0.74141 \dots

Solution steps

0 = - \frac{1}{16} (x - 32)^{2} + 67

Switch sides

- \frac{1}{16} (x - 32)^{2} + 67 = 0

Move

67

to the right side

- \frac{1}{16} (x - 32)^{2} = - 67

Multiply both sides by

- 16

(x - 32)^{2} = 1072

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 32 = 1072 : x = 467 + 32

Solve

x - 32 = - 1072 : x = - 467 + 32

The solutions to the quadratic equation are:

x = 467 + 32, x = - 467 + 32

x^{2} - 8 x - 9 = 0

x^{3} + x^{2} + 4 x + 4

\frac{x}{3} = \frac{5}{8}

- 7 x + 1 \geq 22 or - 10 x + 41 \geq 81

(2 x + 10)^{2} = 4 (x + 5)^{2}

What are the solutions to the equation 0=-1/16 (x-32)^2+67 ?
The solutions to the equation 0=-1/16 (x-32)^2+67 are x=4sqrt(67)+32,x=-4sqrt(67)+32
Find the zeros of 0=-1/16 (x-32)^2+67
The zeros of 0=-1/16 (x-32)^2+67 are x=4sqrt(67)+32,x=-4sqrt(67)+32