What are the solutions to the equation x^2+x+32=0 ?

The solutions to the equation x^2+x+32=0 are x=-1/2+i(sqrt(127))/2 ,x=-1/2-i(sqrt(127))/2

Find the zeros of x^2+x+32=0

The zeros of x^2+x+32=0 are x=-1/2+i(sqrt(127))/2 ,x=-1/2-i(sqrt(127))/2

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x^{2} + x + 32 = 0

x = - \frac{1}{2} + i \frac{127}{2}, x = - \frac{1}{2} - i \frac{127}{2}

Solution steps

x^{2} + x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 32 : 127 i

x_{1, 2} = \frac{- 1 \pm 127 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 127 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 127 i}{2 \cdot 1}

x = \frac{- 1 + 127 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{127}{2}

x = \frac{- 1 - 127 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{127}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{127}{2}, x = - \frac{1}{2} - i \frac{127}{2}

y, (x + y)^{2} = x

r^{2} - 8 r - 22 = 6

78 = π r^{2} (\frac{101}{360})

20 = 0.9 v - 0.01 v^{2}

3 x^{2} + 4 x + 1 = 0

What are the solutions to the equation x^2+x+32=0 ?
The solutions to the equation x^2+x+32=0 are x=-1/2+i(sqrt(127))/2 ,x=-1/2-i(sqrt(127))/2
Find the zeros of x^2+x+32=0
The zeros of x^2+x+32=0 are x=-1/2+i(sqrt(127))/2 ,x=-1/2-i(sqrt(127))/2