What are the solutions to the equation 5x^2=-2 ?

The solutions to the equation 5x^2=-2 are x=sqrt(2/5)i,x=-sqrt(2/5)i

Find the zeros of 5x^2=-2

The zeros of 5x^2=-2 are x=sqrt(2/5)i,x=-sqrt(2/5)i

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5 x^{2} = - 2

x = \frac{2}{5} i, x = - \frac{2}{5} i

Solution steps

5 x^{2} = - 2

Divide both sides by

5

x^{2} = - \frac{2}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{5}, x = - - \frac{2}{5}

- \frac{2}{5} = \frac{2}{5} i

- - \frac{2}{5} = - \frac{2}{5} i

x = \frac{2}{5} i, x = - \frac{2}{5} i

5 x^{2} = - x

0 = 3 x^{2} + 2

8 n^{2} - n - 10 = 0

9 u^{2} - 30 u + 25 = 0

\frac{x}{2} = \frac{x ^{2}}{25}

What are the solutions to the equation 5x^2=-2 ?
The solutions to the equation 5x^2=-2 are x=sqrt(2/5)i,x=-sqrt(2/5)i
Find the zeros of 5x^2=-2
The zeros of 5x^2=-2 are x=sqrt(2/5)i,x=-sqrt(2/5)i