What are the solutions to the equation 7m^2+2m-4=0 ?

The solutions to the equation 7m^2+2m-4=0 are m=(-1+sqrt(29))/7 ,m=-(1+sqrt(29))/7

Find the zeros of 7m^2+2m-4=0

The zeros of 7m^2+2m-4=0 are m=(-1+sqrt(29))/7 ,m=-(1+sqrt(29))/7

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7 m^{2} + 2 m - 4 = 0

m = \frac{- 1 + 29}{7}, m = - \frac{1 + 29}{7}

Decimal Notation

m = 0.62645 \dots, m = - 0.91216 \dots

Solution steps

7 m^{2} + 2 m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 ( - 4 )}{2 \cdot 7}

2^{2} - 4 \cdot 7 (- 4) = 229

m_{1, 2} = \frac{- 2 \pm 2 29}{2 \cdot 7}

Separate the solutions

m_{1} = \frac{- 2 + 2 29}{2 \cdot 7}, m_{2} = \frac{- 2 - 2 29}{2 \cdot 7}

m = \frac{- 2 + 2 29}{2 \cdot 7} : \frac{- 1 + 29}{7}

m = \frac{- 2 - 2 29}{2 \cdot 7} : - \frac{1 + 29}{7}

The solutions to the quadratic equation are:

m = \frac{- 1 + 29}{7}, m = - \frac{1 + 29}{7}

h, (7 - h)^{2} + (2 - k)^{2} = 0

x (x - 35) = 0

13 x^{2} - 39 = - 26 x

36 = x^{2} - 5 x

x^{2} - 2.4 x + 0.7 = 0

What are the solutions to the equation 7m^2+2m-4=0 ?
The solutions to the equation 7m^2+2m-4=0 are m=(-1+sqrt(29))/7 ,m=-(1+sqrt(29))/7
Find the zeros of 7m^2+2m-4=0
The zeros of 7m^2+2m-4=0 are m=(-1+sqrt(29))/7 ,m=-(1+sqrt(29))/7