What are the solutions to the equation p^2+7p=0 ?

The solutions to the equation p^2+7p=0 are p=0,p=-7

Find the zeros of p^2+7p=0

The zeros of p^2+7p=0 are p=0,p=-7

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p^{2} + 7 p = 0

p = 0, p = - 7

Solution steps

p^{2} + 7 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

p_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 7 + 7}{2 \cdot 1}, p_{2} = \frac{- 7 - 7}{2 \cdot 1}

p = \frac{- 7 + 7}{2 \cdot 1} : 0

p = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

p = 0, p = - 7

3 x^{2} + 4 x + 1

3 x^{2} + 4 x - 3

\frac{g ^{2}}{200} (114 + 115) = 20

- \frac{1}{4} x^{2} - 2 x - 4 = 0

4 p^{2} - 8 p - 5 = 0

What are the solutions to the equation p^2+7p=0 ?
The solutions to the equation p^2+7p=0 are p=0,p=-7
Find the zeros of p^2+7p=0
The zeros of p^2+7p=0 are p=0,p=-7