What are the solutions to the equation 3y^2-4y-15=0 ?

The solutions to the equation 3y^2-4y-15=0 are y=3,y=-5/3

Find the zeros of 3y^2-4y-15=0

The zeros of 3y^2-4y-15=0 are y=3,y=-5/3

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3 y^{2} - 4 y - 15 = 0

y = 3, y = - \frac{5}{3}

Decimal Notation

y = 3, y = - 1.66666 \dots

Solution steps

3 y^{2} - 4 y - 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 15) = 14

y_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 3}, y_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 3}

y = \frac{- ( - 4 ) + 14}{2 \cdot 3} : 3

y = \frac{- ( - 4 ) - 14}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

y = 3, y = - \frac{5}{3}

x, x^{2} + y^{2} + z^{2} + 4 x y + 2 x z - 2 yz = 12

f^{2} = 16

2 5^{2} + 6 0^{2} = x^{2}

k^{2} - 1 = 0

x, 3 y^{2} - 2 x^{2} = 2 x y

What are the solutions to the equation 3y^2-4y-15=0 ?
The solutions to the equation 3y^2-4y-15=0 are y=3,y=-5/3
Find the zeros of 3y^2-4y-15=0
The zeros of 3y^2-4y-15=0 are y=3,y=-5/3