What are the solutions to the equation 3g^2+4g-9=0 ?

The solutions to the equation 3g^2+4g-9=0 are g=(-2+sqrt(31))/3 ,g=-(2+sqrt(31))/3

Find the zeros of 3g^2+4g-9=0

The zeros of 3g^2+4g-9=0 are g=(-2+sqrt(31))/3 ,g=-(2+sqrt(31))/3

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3 g^{2} + 4 g - 9 = 0

g = \frac{- 2 + 31}{3}, g = - \frac{2 + 31}{3}

Decimal Notation

g = 1.18925 \dots, g = - 2.52258 \dots

Solution steps

3 g^{2} + 4 g - 9 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 9) = 231

g_{1, 2} = \frac{- 4 \pm 2 31}{2 \cdot 3}

Separate the solutions

g_{1} = \frac{- 4 + 2 31}{2 \cdot 3}, g_{2} = \frac{- 4 - 2 31}{2 \cdot 3}

g = \frac{- 4 + 2 31}{2 \cdot 3} : \frac{- 2 + 31}{3}

g = \frac{- 4 - 2 31}{2 \cdot 3} : - \frac{2 + 31}{3}

The solutions to the quadratic equation are:

g = \frac{- 2 + 31}{3}, g = - \frac{2 + 31}{3}

x, z = - 4 x^{2} - 6 x y - 3 y^{2} + 2 x + y + 10

(x - 3)^{2} + 6 = - 30

x^{2} - 7 x - 98 = 0

9 y^{2} - 42 y - 245 = 0

x, - x^{2} + 4 y^{2} + 2 z^{2} = 8

What are the solutions to the equation 3g^2+4g-9=0 ?
The solutions to the equation 3g^2+4g-9=0 are g=(-2+sqrt(31))/3 ,g=-(2+sqrt(31))/3
Find the zeros of 3g^2+4g-9=0
The zeros of 3g^2+4g-9=0 are g=(-2+sqrt(31))/3 ,g=-(2+sqrt(31))/3