What are the solutions to the equation 2x^2-6x-36=0 ?

The solutions to the equation 2x^2-6x-36=0 are x=6,x=-3

Find the zeros of 2x^2-6x-36=0

The zeros of 2x^2-6x-36=0 are x=6,x=-3

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2 x^{2} - 6 x - 36 = 0

x = 6, x = - 3

Solution steps

2 x^{2} - 6 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 36 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 36) = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 2}

x = \frac{- ( - 6 ) + 18}{2 \cdot 2} : 6

x = \frac{- ( - 6 ) - 18}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 6, x = - 3

18 n^{2} - 50

(- 2)^{\frac{1}{3}}

i^{88}

49 x^{2} + 81 = 0

4 x^{3} y^{4} z^{3} + 2 x^{2} y^{3} z - 6 x^{2} y^{3} z^{2}

What are the solutions to the equation 2x^2-6x-36=0 ?
The solutions to the equation 2x^2-6x-36=0 are x=6,x=-3
Find the zeros of 2x^2-6x-36=0
The zeros of 2x^2-6x-36=0 are x=6,x=-3