What are the solutions to the equation 12^2=x\times x+7 ?

The solutions to the equation 12^2=x\times x+7 are x=sqrt(137),x=-sqrt(137)

Find the zeros of 12^2=x\times x+7

The zeros of 12^2=x\times x+7 are x=sqrt(137),x=-sqrt(137)

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1 2^{2} = x \cdot x + 7

x = 137, x = - 137

Decimal

x = 11.70469 \dots, x = - 11.70469 \dots

Solution steps

1 2^{2} = xx + 7

Switch sides

xx + 7 = 1 2^{2}

Move

7

to the right side

xx = 137

Simplify

x^{2} = 137

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 137, x = - 137

(x - 2 - 5) (x - 2 + 5) = 0

15 x^{2} - 4 x = 0

15 x^{2} + 7 x - 12 = 3 x^{2} + x - 12

40 (- 3 x^{2} - 4) = 0

r^{2} - 7 r + 10 = 0

What are the solutions to the equation 12^2=x\times x+7 ?
The solutions to the equation 12^2=x\times x+7 are x=sqrt(137),x=-sqrt(137)
Find the zeros of 12^2=x\times x+7
The zeros of 12^2=x\times x+7 are x=sqrt(137),x=-sqrt(137)