What are the solutions to the equation (6x-1)^2=-8 ?

The solutions to the equation (6x-1)^2=-8 are x= 1/6+i(sqrt(2))/3 ,x= 1/6-i(sqrt(2))/3

Find the zeros of (6x-1)^2=-8

The zeros of (6x-1)^2=-8 are x= 1/6+i(sqrt(2))/3 ,x= 1/6-i(sqrt(2))/3

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(6 x - 1)^{2} = - 8

x = \frac{1}{6} + i \frac{2}{3}, x = \frac{1}{6} - i \frac{2}{3}

Solution steps

(6 x - 1)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 x - 1 = - 8 : x = \frac{1}{6} + i \frac{2}{3}

Solve

6 x - 1 = - - 8 : x = \frac{1}{6} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{2}{3}, x = \frac{1}{6} - i \frac{2}{3}

9^{2} = 4. 5^{2} + x^{2}

81 x^{2} - 256 = 0

x^{2} + 23 x + 102 = 0

(x - 2) (2 x + 3) = x + 1

(m - 3) x^{2} - 2 m x + m + 2 = 0

What are the solutions to the equation (6x-1)^2=-8 ?
The solutions to the equation (6x-1)^2=-8 are x= 1/6+i(sqrt(2))/3 ,x= 1/6-i(sqrt(2))/3
Find the zeros of (6x-1)^2=-8
The zeros of (6x-1)^2=-8 are x= 1/6+i(sqrt(2))/3 ,x= 1/6-i(sqrt(2))/3