What are the solutions to the equation x^2-15x=-12-7x ?

The solutions to the equation x^2-15x=-12-7x are x=6,x=2

Find the zeros of x^2-15x=-12-7x

The zeros of x^2-15x=-12-7x are x=6,x=2

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x^{2} - 15 x = - 12 - 7 x

x = 6, x = 2

Solution steps

x^{2} - 15 x = - 12 - 7 x

Move

7 x

to the left side

x^{2} - 8 x = - 12

Move

12

to the left side

x^{2} - 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 12 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4}{2 \cdot 1} : 6

x = \frac{- ( - 8 ) - 4}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

x, 4 x^{2} + y^{2} = - 1

(x - 3)^{2} + (x + 3)^{2} = 9

x^{2} + 2000 x + 1 0^{6} = 0

12 x^{2} - 13 x - 14 = 0

x, 5 x^{2} - 3 x y + 5 y^{2} - 10 x - 20 y - 10 = 0

What are the solutions to the equation x^2-15x=-12-7x ?
The solutions to the equation x^2-15x=-12-7x are x=6,x=2
Find the zeros of x^2-15x=-12-7x
The zeros of x^2-15x=-12-7x are x=6,x=2