What are the solutions to the equation k^2-4k+4=0 ?

The solutions to the equation k^2-4k+4=0 are k=2

Find the zeros of k^2-4k+4=0

The zeros of k^2-4k+4=0 are k=2

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k^{2} - 4 k + 4 = 0

k = 2

Solution steps

k^{2} - 4 k + 4 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

k_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

k = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

k = 2

The solution to the quadratic equation is:

k = 2

x, - x^{2} + \frac{9 y ^{2}}{4} = 0

10 + 3 x = x^{2}

3 x^{2} - 9 x - 5 = 0

w^{2} - 35 w = 0

64.77 + 25.96 T + 0.02134 T^{2} = 0

What are the solutions to the equation k^2-4k+4=0 ?
The solutions to the equation k^2-4k+4=0 are k=2
Find the zeros of k^2-4k+4=0
The zeros of k^2-4k+4=0 are k=2