What are the solutions to the equation x^2-8=-7x ?

The solutions to the equation x^2-8=-7x are x=1,x=-8

Find the zeros of x^2-8=-7x

The zeros of x^2-8=-7x are x=1,x=-8

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x^{2} - 8 = - 7 x

x = 1, x = - 8

Solution steps

x^{2} - 8 = - 7 x

Move

7 x

to the left side

x^{2} - 8 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 7 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 8) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 1}, x_{2} = \frac{- 7 - 9}{2 \cdot 1}

x = \frac{- 7 + 9}{2 \cdot 1} : 1

x = \frac{- 7 - 9}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 1, x = - 8

\frac{2}{6}

i + i

3 - 8

0.75 p = 0.4 p + 100

(49 t - 16 t^{2}) - 34

What are the solutions to the equation x^2-8=-7x ?
The solutions to the equation x^2-8=-7x are x=1,x=-8
Find the zeros of x^2-8=-7x
The zeros of x^2-8=-7x are x=1,x=-8