What are the solutions to the equation 4n^2+3n=3 ?

The solutions to the equation 4n^2+3n=3 are n=(-3+sqrt(57))/8 ,n=(-3-sqrt(57))/8

Find the zeros of 4n^2+3n=3

The zeros of 4n^2+3n=3 are n=(-3+sqrt(57))/8 ,n=(-3-sqrt(57))/8

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4 n^{2} + 3 n = 3

n = \frac{- 3 + 57}{8}, n = \frac{- 3 - 57}{8}

Decimal

n = 0.56872 \dots, n = - 1.31872 \dots

Solution steps

4 n^{2} + 3 n = 3

Move

3

to the left side

4 n^{2} + 3 n - 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 3) = 57

n_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- 3 + 57}{2 \cdot 4}, n_{2} = \frac{- 3 - 57}{2 \cdot 4}

n = \frac{- 3 + 57}{2 \cdot 4} : \frac{- 3 + 57}{8}

n = \frac{- 3 - 57}{2 \cdot 4} : \frac{- 3 - 57}{8}

The solutions to the quadratic equation are:

n = \frac{- 3 + 57}{8}, n = \frac{- 3 - 57}{8}

- 2 x^{2} + 3 x - 7 = 0

8 x^{2} - 6 x - 1 = 0

100 x^{2} + 3 = 7

(x^{2} - 1) = 3

32 x^{2} - 3 x - 14 = (2 x - 1)^{2}

What are the solutions to the equation 4n^2+3n=3 ?
The solutions to the equation 4n^2+3n=3 are n=(-3+sqrt(57))/8 ,n=(-3-sqrt(57))/8
Find the zeros of 4n^2+3n=3
The zeros of 4n^2+3n=3 are n=(-3+sqrt(57))/8 ,n=(-3-sqrt(57))/8