What are the solutions to the equation x^2+12x+50=0 ?

The solutions to the equation x^2+12x+50=0 are x=-6+sqrt(14)i,x=-6-sqrt(14)i

Find the zeros of x^2+12x+50=0

The zeros of x^2+12x+50=0 are x=-6+sqrt(14)i,x=-6-sqrt(14)i

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x^{2} + 12 x + 50 = 0

x = - 6 + 14 i, x = - 6 - 14 i

Solution steps

x^{2} + 12 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 50 : 214 i

x_{1, 2} = \frac{- 12 \pm 2 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 14 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 14 i}{2 \cdot 1}

x = \frac{- 12 + 2 14 i}{2 \cdot 1} : - 6 + 14 i

x = \frac{- 12 - 2 14 i}{2 \cdot 1} : - 6 - 14 i

The solutions to the quadratic equation are:

x = - 6 + 14 i, x = - 6 - 14 i

\frac{3 ( x - 1 )}{5} \frac{4 ( x + 2 )}{3} = \frac{2}{7}

- x^{2} + 24 x - 128 = 0

x^{2} + 4 x + 4 = 3

0 = t^{2} - 8 t + 7

x (x - 2) = 2 (x + 6)

What are the solutions to the equation x^2+12x+50=0 ?
The solutions to the equation x^2+12x+50=0 are x=-6+sqrt(14)i,x=-6-sqrt(14)i
Find the zeros of x^2+12x+50=0
The zeros of x^2+12x+50=0 are x=-6+sqrt(14)i,x=-6-sqrt(14)i