What are the solutions to the equation 2g^2-32=-32 ?

The solutions to the equation 2g^2-32=-32 are g=0

Find the zeros of 2g^2-32=-32

The zeros of 2g^2-32=-32 are g=0

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2 g^{2} - 32 = - 32

g = 0

Solution steps

2 g^{2} - 32 = - 32

Move

32

to the right side

2 g^{2} = 0

Divide both sides by

2

g = 0

9 a^{2} + 6 a - 17 = 0

x^{2} = \frac{9}{25}

3 b^{2} + 2 b + 3 = 12 b^{2} + 4 b + 3

x - 1 = - x^{2} + x + 1

0 = 3 x^{2} + 5 x + 2

What are the solutions to the equation 2g^2-32=-32 ?
The solutions to the equation 2g^2-32=-32 are g=0
Find the zeros of 2g^2-32=-32
The zeros of 2g^2-32=-32 are g=0