What are the solutions to the equation -6x^2-4x=-9 ?

The solutions to the equation -6x^2-4x=-9 are x=-(2+sqrt(58))/6 ,x=(sqrt(58)-2)/6

Find the zeros of -6x^2-4x=-9

The zeros of -6x^2-4x=-9 are x=-(2+sqrt(58))/6 ,x=(sqrt(58)-2)/6

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- 6 x^{2} - 4 x = - 9

x = - \frac{2 + 58}{6}, x = \frac{58 - 2}{6}

Decimal Notation

x = - 1.60262 \dots, x = 0.93596 \dots

Solution steps

- 6 x^{2} - 4 x = - 9

Move

9

to the left side

- 6 x^{2} - 4 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 6 ) \cdot 9}{2 ( - 6 )}

(- 4)^{2} - 4 (- 6) \cdot 9 = 258

x_{1, 2} = \frac{- ( - 4 ) \pm 2 58}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 58}{2 ( - 6 )}, x_{2} = \frac{- ( - 4 ) - 2 58}{2 ( - 6 )}

x = \frac{- ( - 4 ) + 2 58}{2 ( - 6 )} : - \frac{2 + 58}{6}

x = \frac{- ( - 4 ) - 2 58}{2 ( - 6 )} : \frac{58 - 2}{6}

The solutions to the quadratic equation are:

x = - \frac{2 + 58}{6}, x = \frac{58 - 2}{6}

m^{2} + 80 m + 1200 = 0

x, x^{2} - 6 x + 13 = 0

\frac{y ( 2 y - 1 )}{2} = \frac{1 - y}{3}

4 x^{2} + 8 x + 3 = 8

8 - 2 x - x^{2} = 0

What are the solutions to the equation -6x^2-4x=-9 ?
The solutions to the equation -6x^2-4x=-9 are x=-(2+sqrt(58))/6 ,x=(sqrt(58)-2)/6
Find the zeros of -6x^2-4x=-9
The zeros of -6x^2-4x=-9 are x=-(2+sqrt(58))/6 ,x=(sqrt(58)-2)/6