What are the solutions to the equation 12x+12=16x^2-16x+4 ?

The solutions to the equation 12x+12=16x^2-16x+4 are x=2,x=-1/4

Find the zeros of 12x+12=16x^2-16x+4

The zeros of 12x+12=16x^2-16x+4 are x=2,x=-1/4

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12 x + 12 = 16 x^{2} - 16 x + 4

x = 2, x = - \frac{1}{4}

Decimal Notation

x = 2, x = - 0.25

Solution steps

12 x + 12 = 16 x^{2} - 16 x + 4

Switch sides

16 x^{2} - 16 x + 4 = 12 x + 12

Move

12

to the left side

16 x^{2} - 16 x - 8 = 12 x

Move

12 x

to the left side

16 x^{2} - 28 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 16 ( - 8 )}{2 \cdot 16}

(- 28)^{2} - 4 \cdot 16 (- 8) = 36

x_{1, 2} = \frac{- ( - 28 ) \pm 36}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 36}{2 \cdot 16}, x_{2} = \frac{- ( - 28 ) - 36}{2 \cdot 16}

x = \frac{- ( - 28 ) + 36}{2 \cdot 16} : 2

x = \frac{- ( - 28 ) - 36}{2 \cdot 16} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{4}

12 x^{2} = 16

(x - 5) (2 x + 3) = - 2 x - 3

x^{2} = 35 + 2 x

3 x^{2} + 2 x - 1 = 0

119 = 6 n^{2} - 1

What are the solutions to the equation 12x+12=16x^2-16x+4 ?
The solutions to the equation 12x+12=16x^2-16x+4 are x=2,x=-1/4
Find the zeros of 12x+12=16x^2-16x+4
The zeros of 12x+12=16x^2-16x+4 are x=2,x=-1/4