What are the solutions to the equation 3x-3x^2=0 ?

The solutions to the equation 3x-3x^2=0 are x=0,x=1

Find the zeros of 3x-3x^2=0

The zeros of 3x-3x^2=0 are x=0,x=1

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3 x - 3 x^{2} = 0

x = 0, x = 1

Solution steps

3 x - 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

3^{2} - 4 (- 3) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 3 )}, x_{2} = \frac{- 3 - 3}{2 ( - 3 )}

x = \frac{- 3 + 3}{2 ( - 3 )} : 0

x = \frac{- 3 - 3}{2 ( - 3 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

15 x^{2} - 4 x - 4 = 0

x^{2} = 27 x

x^{2} = 245

(2 x - 1) (8 x - 4) = - 1

(x + 6) (x + 6) = 0

What are the solutions to the equation 3x-3x^2=0 ?
The solutions to the equation 3x-3x^2=0 are x=0,x=1
Find the zeros of 3x-3x^2=0
The zeros of 3x-3x^2=0 are x=0,x=1