What are the solutions to the equation 3x^2-12x=12 ?

The solutions to the equation 3x^2-12x=12 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

Find the zeros of 3x^2-12x=12

The zeros of 3x^2-12x=12 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

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3 x^{2} - 12 x = 12

x = 2 (1 + 2), x = 2 (1 - 2)

Decimal Notation

x = 4.82842 \dots, x = - 0.82842 \dots

Solution steps

3 x^{2} - 12 x = 12

Move

12

to the left side

3 x^{2} - 12 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 12) = 122

x_{1, 2} = \frac{- ( - 12 ) \pm 12 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 2}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 12 2}{2 \cdot 3}

x = \frac{- ( - 12 ) + 12 2}{2 \cdot 3} : 2 (1 + 2)

x = \frac{- ( - 12 ) - 12 2}{2 \cdot 3} : 2 (1 - 2)

The solutions to the quadratic equation are:

x = 2 (1 + 2), x = 2 (1 - 2)

6 x^{2} + 30 x - 144 = 0

5 x + 14 = x^{2}

(w + 7)^{2} = 121

4320 = 3000 (1 + r)^{2}

x, \frac{y ^{2}}{9} - \frac{x ^{2}}{25} = 0

What are the solutions to the equation 3x^2-12x=12 ?
The solutions to the equation 3x^2-12x=12 are x=2(1+sqrt(2)),x=2(1-sqrt(2))
Find the zeros of 3x^2-12x=12
The zeros of 3x^2-12x=12 are x=2(1+sqrt(2)),x=2(1-sqrt(2))