What are the solutions to the equation x^2-8x-6=4 ?

The solutions to the equation x^2-8x-6=4 are x=4+sqrt(26),x=4-sqrt(26)

Find the zeros of x^2-8x-6=4

The zeros of x^2-8x-6=4 are x=4+sqrt(26),x=4-sqrt(26)

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x^{2} - 8 x - 6 = 4

x = 4 + 26, x = 4 - 26

Decimal Notation

x = 9.09901 \dots, x = - 1.09901 \dots

Solution steps

x^{2} - 8 x - 6 = 4

Move

4

to the left side

x^{2} - 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 10) = 226

x_{1, 2} = \frac{- ( - 8 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 26}{2 \cdot 1} : 4 + 26

x = \frac{- ( - 8 ) - 2 26}{2 \cdot 1} : 4 - 26

The solutions to the quadratic equation are:

x = 4 + 26, x = 4 - 26

- 3 x^{2} + 6 x + 21

x^{2} = 768

2 x^{2} - 42 = 0

112 = - 16 x^{2} + 128 x

- 49 p^{2} = 7

What are the solutions to the equation x^2-8x-6=4 ?
The solutions to the equation x^2-8x-6=4 are x=4+sqrt(26),x=4-sqrt(26)
Find the zeros of x^2-8x-6=4
The zeros of x^2-8x-6=4 are x=4+sqrt(26),x=4-sqrt(26)