What are the solutions to the equation 4x^2+16x+7=0 ?

The solutions to the equation 4x^2+16x+7=0 are x=-1/2 ,x=-7/2

Find the zeros of 4x^2+16x+7=0

The zeros of 4x^2+16x+7=0 are x=-1/2 ,x=-7/2

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4 x^{2} + 16 x + 7 = 0

x = - \frac{1}{2}, x = - \frac{7}{2}

Decimal Notation

x = - 0.5, x = - 3.5

Solution steps

4 x^{2} + 16 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 \cdot 7 = 12

x_{1, 2} = \frac{- 16 \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 12}{2 \cdot 4}, x_{2} = \frac{- 16 - 12}{2 \cdot 4}

x = \frac{- 16 + 12}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 16 - 12}{2 \cdot 4} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{7}{2}

22 + 2 a = 37 + 6 + a

8^{- \frac{1}{3}}

4 (6 a + 1) < 16

48 = - 8 b

x - 7 = - 16

What are the solutions to the equation 4x^2+16x+7=0 ?
The solutions to the equation 4x^2+16x+7=0 are x=-1/2 ,x=-7/2
Find the zeros of 4x^2+16x+7=0
The zeros of 4x^2+16x+7=0 are x=-1/2 ,x=-7/2