What are the solutions to the equation -2x+x^2+3/4 =0 ?

The solutions to the equation -2x+x^2+3/4 =0 are x= 3/2 ,x= 1/2

Find the zeros of -2x+x^2+3/4 =0

The zeros of -2x+x^2+3/4 =0 are x= 3/2 ,x= 1/2

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- 2 x + x^{2} + \frac{3}{4} = 0

x = \frac{3}{2}, x = \frac{1}{2}

Decimal Notation

x = 1.5, x = 0.5

Solution steps

- 2 x + x^{2} + \frac{3}{4} = 0

Multiply both sides by

4

4 x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 3 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 8 ) - 4}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{2}

(2 x + 1) (x - 8) = 0

3 x^{2} - 4 x = 20 x + 27

k = r^{2} + 5, 6 \leq r \leq 7

1 x^{2} + 7 x + 15 = 0

3 x^{2} + x

What are the solutions to the equation -2x+x^2+3/4 =0 ?
The solutions to the equation -2x+x^2+3/4 =0 are x= 3/2 ,x= 1/2
Find the zeros of -2x+x^2+3/4 =0
The zeros of -2x+x^2+3/4 =0 are x= 3/2 ,x= 1/2