What are the solutions to the equation (-3)^2+y^2=7^2 ?

The solutions to the equation (-3)^2+y^2=7^2 are y=2sqrt(10),y=-2sqrt(10)

Find the zeros of (-3)^2+y^2=7^2

The zeros of (-3)^2+y^2=7^2 are y=2sqrt(10),y=-2sqrt(10)

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(- 3)^{2} + y^{2} = 7^{2}

y = 210, y = - 210

Decimal Notation

y = 6.32455 \dots, y = - 6.32455 \dots

Solution steps

(- 3)^{2} + y^{2} = 7^{2}

Expand

(- 3)^{2} + y^{2} : 9 + y^{2}

Expand

7^{2} : 49

9 + y^{2} = 49

Move

9

to the right side

y^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 40, y = - 40

40 = 210

- 40 = - 210

y = 210, y = - 210

x^{2} - \frac{x}{2} = 0

12 x^{2} - 46 = 0

x, y = x^{2} + 2 x + 3

x^{2} = 1.4

x^{2} = 1 + x

What are the solutions to the equation (-3)^2+y^2=7^2 ?
The solutions to the equation (-3)^2+y^2=7^2 are y=2sqrt(10),y=-2sqrt(10)
Find the zeros of (-3)^2+y^2=7^2
The zeros of (-3)^2+y^2=7^2 are y=2sqrt(10),y=-2sqrt(10)