What are the solutions to the equation 4x^2-5x+31=0 ?

The solutions to the equation 4x^2-5x+31=0 are x= 5/8+i(sqrt(471))/8 ,x= 5/8-i(sqrt(471))/8

Find the zeros of 4x^2-5x+31=0

The zeros of 4x^2-5x+31=0 are x= 5/8+i(sqrt(471))/8 ,x= 5/8-i(sqrt(471))/8

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4 x^{2} - 5 x + 31 = 0

x = \frac{5}{8} + i \frac{471}{8}, x = \frac{5}{8} - i \frac{471}{8}

Solution steps

4 x^{2} - 5 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 31}{2 \cdot 4}

Simplify

(- 5)^{2} - 4 \cdot 4 \cdot 31 : 471 i

x_{1, 2} = \frac{- ( - 5 ) \pm 471 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 471 i}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 471 i}{2 \cdot 4}

x = \frac{- ( - 5 ) + 471 i}{2 \cdot 4} : \frac{5}{8} + i \frac{471}{8}

x = \frac{- ( - 5 ) - 471 i}{2 \cdot 4} : \frac{5}{8} - i \frac{471}{8}

The solutions to the quadratic equation are:

x = \frac{5}{8} + i \frac{471}{8}, x = \frac{5}{8} - i \frac{471}{8}

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What are the solutions to the equation 4x^2-5x+31=0 ?
The solutions to the equation 4x^2-5x+31=0 are x= 5/8+i(sqrt(471))/8 ,x= 5/8-i(sqrt(471))/8
Find the zeros of 4x^2-5x+31=0
The zeros of 4x^2-5x+31=0 are x= 5/8+i(sqrt(471))/8 ,x= 5/8-i(sqrt(471))/8