What are the solutions to the equation (r+7/8)^2= 1/64 ?

The solutions to the equation (r+7/8)^2= 1/64 are r=-3/4 ,r=-1

Find the zeros of (r+7/8)^2= 1/64

The zeros of (r+7/8)^2= 1/64 are r=-3/4 ,r=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(r + \frac{7}{8})^{2} = \frac{1}{64}

r = - \frac{3}{4}, r = - 1

Decimal Notation

r = - 0.75, r = - 1

Solution steps

(r + \frac{7}{8})^{2} = \frac{1}{64}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r + \frac{7}{8} = \frac{1}{64} : r = - \frac{3}{4}

Solve

r + \frac{7}{8} = - \frac{1}{64} : r = - 1

The solutions to the quadratic equation are:

r = - \frac{3}{4}, r = - 1

3 x^{2} + 48 x + 183 = 0

y^{2} - 5 y + 1 = 0

x^{2} + 8 x - 40 = 0

8 y^{2} + y + 2 = 0

- 20 x^{2} = - 7 x - 6

What are the solutions to the equation (r+7/8)^2= 1/64 ?
The solutions to the equation (r+7/8)^2= 1/64 are r=-3/4 ,r=-1
Find the zeros of (r+7/8)^2= 1/64
The zeros of (r+7/8)^2= 1/64 are r=-3/4 ,r=-1