What are the solutions to the equation b^2-10b+25=0 ?

The solutions to the equation b^2-10b+25=0 are b=5

Find the zeros of b^2-10b+25=0

The zeros of b^2-10b+25=0 are b=5

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b^{2} - 10 b + 25 = 0

b = 5

Solution steps

b^{2} - 10 b + 25 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

b_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

b = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

b = 5

The solution to the quadratic equation is:

b = 5

- 29 x^{2} + 4167 x - 50000 = 0

24 x^{2} + 14 x - 3 = 0

- 3 x^{2} - 5 x = 1

A (X) = X^{2} + π (\frac{1 - 4 X}{2})^{2}

9 X^{2} - 18 X = 0

What are the solutions to the equation b^2-10b+25=0 ?
The solutions to the equation b^2-10b+25=0 are b=5
Find the zeros of b^2-10b+25=0
The zeros of b^2-10b+25=0 are b=5