What are the solutions to the equation 1-0.4x+0.4x^2=0 ?

The solutions to the equation 1-0.4x+0.4x^2=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2

Find the zeros of 1-0.4x+0.4x^2=0

The zeros of 1-0.4x+0.4x^2=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2

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1 - 0.4 x + 0.4 x^{2} = 0

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

1 - 0.4 x + 0.4 x^{2} = 0

Multiply both sides by

10

10 - 4 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 10 : 12 i

x_{1, 2} = \frac{- ( - 4 ) \pm 12 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 12 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 12 i}{2 \cdot 4} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 4 ) - 12 i}{2 \cdot 4} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

s^{2} + 6 s + 45 = 0

x^{2} - 2 + 3 = 0

4 y^{2} + 9 y^{2} = 36

0 = 3 x^{2} + 6 x + 5

x^{2} + (1)^{2} = 4

What are the solutions to the equation 1-0.4x+0.4x^2=0 ?
The solutions to the equation 1-0.4x+0.4x^2=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2
Find the zeros of 1-0.4x+0.4x^2=0
The zeros of 1-0.4x+0.4x^2=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2