What are the solutions to the equation (2x^2+3)=8x+3 ?

The solutions to the equation (2x^2+3)=8x+3 are x=4,x=0

Find the zeros of (2x^2+3)=8x+3

The zeros of (2x^2+3)=8x+3 are x=4,x=0

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(2 x^{2} + 3) = 8 x + 3

x = 4, x = 0

Solution steps

(2 x^{2} + 3) = 8 x + 3

Refine

2 x^{2} + 3 = 8 x + 3

Move

3

to the left side

2 x^{2} = 8 x

Move

8 x

to the left side

2 x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 2}

x = \frac{- ( - 8 ) + 8}{2 \cdot 2} : 4

x = \frac{- ( - 8 ) - 8}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

6 x^{2} - 4 x - 5 = 0

x (3)^{2} + 3 x^{2} - 3 + 3^{2} = 0

2 r^{2} + 9 r + 4 = 0

5 x^{2} - 31 x + 30 = 0

x, x^{2} + x y + y^{2} = 27

What are the solutions to the equation (2x^2+3)=8x+3 ?
The solutions to the equation (2x^2+3)=8x+3 are x=4,x=0
Find the zeros of (2x^2+3)=8x+3
The zeros of (2x^2+3)=8x+3 are x=4,x=0