What are the solutions to the equation u^2+u=650 ?

The solutions to the equation u^2+u=650 are u=25,u=-26

Find the zeros of u^2+u=650

The zeros of u^2+u=650 are u=25,u=-26

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u^{2} + u = 650

u = 25, u = - 26

Solution steps

u^{2} + u = 650

Move

650

to the left side

u^{2} + u - 650 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 650 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 650) = 51

u_{1, 2} = \frac{- 1 \pm 51}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 1 + 51}{2 \cdot 1}, u_{2} = \frac{- 1 - 51}{2 \cdot 1}

u = \frac{- 1 + 51}{2 \cdot 1} : 25

u = \frac{- 1 - 51}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

u = 25, u = - 26

8 = x^{2} + x

x^{2} = 2 x - 15

16 t^{2} - 201 t + 93 = 0

6 = x^{2} - 4 x

6 x^{2} - 47 x - 63 = 0

What are the solutions to the equation u^2+u=650 ?
The solutions to the equation u^2+u=650 are u=25,u=-26
Find the zeros of u^2+u=650
The zeros of u^2+u=650 are u=25,u=-26