What are the solutions to the equation 5x^2-3x+a-1=0.7 ?

The solutions to the equation 5x^2-3x+a-1=0.7 are x=(3+sqrt(-20a+43))/(10),x=(3-sqrt(-20a+43))/(10)

Find the zeros of 5x^2-3x+a-1=0.7

The zeros of 5x^2-3x+a-1=0.7 are x=(3+sqrt(-20a+43))/(10),x=(3-sqrt(-20a+43))/(10)

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5 x^{2} - 3 x + a - 1 = 0.7

x = \frac{3 + - 20 a + 43}{10}, x = \frac{3 - - 20 a + 43}{10}

Solution steps

5 x^{2} - 3 x + a - 1 = 0.7

Multiply both sides by

10

50 x^{2} - 30 x + 10 a - 10 = 7

Move

7

to the left side

50 x^{2} - 30 x + 10 a - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 50 ( 10 a - 17 )}{2 \cdot 50}

Simplify

(- 30)^{2} - 4 \cdot 50 (10 a - 17) : 10 - 20 a + 43

x_{1, 2} = \frac{- ( - 30 ) \pm 10 - 20 a + 43}{2 \cdot 50}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 10 - 20 a + 43}{2 \cdot 50}, x_{2} = \frac{- ( - 30 ) - 10 - 20 a + 43}{2 \cdot 50}

x = \frac{- ( - 30 ) + 10 - 20 a + 43}{2 \cdot 50} : \frac{3 + - 20 a + 43}{10}

x = \frac{- ( - 30 ) - 10 - 20 a + 43}{2 \cdot 50} : \frac{3 - - 20 a + 43}{10}

The solutions to the quadratic equation are:

x = \frac{3 + - 20 a + 43}{10}, x = \frac{3 - - 20 a + 43}{10}

x, x^{2} + y^{2} + 4 x - 3 y + 9 = 0

x^{2} - 17 + 52 = 0

0.25 s^{2} + 1.5 s + 2 - 1 = 0

x, (x^{2} + y^{2} - 1) 3 - x^{2} y^{3} = 0

y = - y^{2} + 2

What are the solutions to the equation 5x^2-3x+a-1=0.7 ?
The solutions to the equation 5x^2-3x+a-1=0.7 are x=(3+sqrt(-20a+43))/(10),x=(3-sqrt(-20a+43))/(10)
Find the zeros of 5x^2-3x+a-1=0.7
The zeros of 5x^2-3x+a-1=0.7 are x=(3+sqrt(-20a+43))/(10),x=(3-sqrt(-20a+43))/(10)