What are the solutions to the equation x^2+3x-27=0 ?

The solutions to the equation x^2+3x-27=0 are x=(-3+3sqrt(13))/2 ,x=(-3-3sqrt(13))/2

Find the zeros of x^2+3x-27=0

The zeros of x^2+3x-27=0 are x=(-3+3sqrt(13))/2 ,x=(-3-3sqrt(13))/2

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x^{2} + 3 x - 27 = 0

x = \frac{- 3 + 3 13}{2}, x = \frac{- 3 - 3 13}{2}

Decimal Notation

x = 3.90832 \dots, x = - 6.90832 \dots

Solution steps

x^{2} + 3 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 27) = 313

x_{1, 2} = \frac{- 3 \pm 3 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3 13}{2 \cdot 1}, x_{2} = \frac{- 3 - 3 13}{2 \cdot 1}

x = \frac{- 3 + 3 13}{2 \cdot 1} : \frac{- 3 + 3 13}{2}

x = \frac{- 3 - 3 13}{2 \cdot 1} : \frac{- 3 - 3 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3 13}{2}, x = \frac{- 3 - 3 13}{2}

250 = (4 w - 2) (w)

a, m (a) = - 0.2 a^{2} + 7 a + 68

x, 9 x^{2} - 4 x y + 6 y^{2} - 10 x - 20 y = 5

- 6 x^{2} + 54 x + 132 = 0

r, r^{2} + 9 = 0

What are the solutions to the equation x^2+3x-27=0 ?
The solutions to the equation x^2+3x-27=0 are x=(-3+3sqrt(13))/2 ,x=(-3-3sqrt(13))/2
Find the zeros of x^2+3x-27=0
The zeros of x^2+3x-27=0 are x=(-3+3sqrt(13))/2 ,x=(-3-3sqrt(13))/2