What are the solutions to the equation 2(x^2-2x)+13=-7 ?

The solutions to the equation 2(x^2-2x)+13=-7 are x=1+3i,x=1-3i

Find the zeros of 2(x^2-2x)+13=-7

The zeros of 2(x^2-2x)+13=-7 are x=1+3i,x=1-3i

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2 (x^{2} - 2 x) + 13 = - 7

x = 1 + 3 i, x = 1 - 3 i

Solution steps

2 (x^{2} - 2 x) + 13 = - 7

Expand

2 (x^{2} - 2 x) + 13 : 2 x^{2} - 4 x + 13

2 x^{2} - 4 x + 13 = - 7

Move

7

to the left side

2 x^{2} - 4 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

Simplify

(- 4)^{2} - 4 \cdot 2 \cdot 20 : 12 i

x_{1, 2} = \frac{- ( - 4 ) \pm 12 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12 i}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 12 i}{2 \cdot 2}

x = \frac{- ( - 4 ) + 12 i}{2 \cdot 2} : 1 + 3 i

x = \frac{- ( - 4 ) - 12 i}{2 \cdot 2} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

y, x = y - y^{2}

- 2 a \cdot 3 a = 25

x^{2} + 24 x + 102 = 0

n, m + 2 n^{2} = 7 m

x (x + 3) = 88

What are the solutions to the equation 2(x^2-2x)+13=-7 ?
The solutions to the equation 2(x^2-2x)+13=-7 are x=1+3i,x=1-3i
Find the zeros of 2(x^2-2x)+13=-7
The zeros of 2(x^2-2x)+13=-7 are x=1+3i,x=1-3i