What are the solutions to the equation -4=x(x-4) ?

The solutions to the equation -4=x(x-4) are x=2

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-4=x(x-4)

- 4 = x (x - 4)

x = 2

Solution steps

- 4 = x (x - 4)

Expand

x (x - 4) : x^{2} - 4 x

- 4 = x^{2} - 4 x

Switch sides

x^{2} - 4 x = - 4

Move

4

to the left side

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

x (x + 3) = - 1

4 x^{2} + 6 x - 28 = 0

(x + 5) (x - 5) = 3 x - 2

0 = 5 x^{2} + 15

4 (x - 6)^{2} - 5 = 319

What are the solutions to the equation -4=x(x-4) ?
The solutions to the equation -4=x(x-4) are x=2
Find the zeros of -4=x(x-4)
The zeros of -4=x(x-4) are x=2