What are the solutions to the equation 25x^2+50x+25=0 ?

The solutions to the equation 25x^2+50x+25=0 are x=-1

Find the zeros of 25x^2+50x+25=0

The zeros of 25x^2+50x+25=0 are x=-1

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25 x^{2} + 50 x + 25 = 0

x = - 1

Solution steps

25 x^{2} + 50 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 25 \cdot 25}{2 \cdot 25}

5 0^{2} - 4 \cdot 25 \cdot 25 = 0

x_{1, 2} = \frac{- 50 \pm 0}{2 \cdot 25}

x = \frac{- 50}{2 \cdot 25}

\frac{- 50}{2 \cdot 25} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

2 x^{2} + 2 x - 2 = 0

x, x^{2} + y^{2} - \frac{z ^{2}}{4} = 1

a, a^{2} + b^{2} + 1 = ab + a + b

x, 5 x^{2} - 15 x = 0

9 = (x + 1)^{2}

What are the solutions to the equation 25x^2+50x+25=0 ?
The solutions to the equation 25x^2+50x+25=0 are x=-1
Find the zeros of 25x^2+50x+25=0
The zeros of 25x^2+50x+25=0 are x=-1