What are the solutions to the equation v^2=-11v ?

The solutions to the equation v^2=-11v are v=0,v=-11

Find the zeros of v^2=-11v

The zeros of v^2=-11v are v=0,v=-11

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v^{2} = - 11 v

v = 0, v = - 11

Solution steps

v^{2} = - 11 v

Move

11 v

to the left side

v^{2} + 11 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 0 = 11

v_{1, 2} = \frac{- 11 \pm 11}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 11 + 11}{2 \cdot 1}, v_{2} = \frac{- 11 - 11}{2 \cdot 1}

v = \frac{- 11 + 11}{2 \cdot 1} : 0

v = \frac{- 11 - 11}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

v = 0, v = - 11

2 x^{2} - 5 x = - 8

n^{2} - 15 n + 56 = 0

v^{2} = - 100

y^{2} - 6 y + 16 = 0

y^{2} = 8 - y^{2}

What are the solutions to the equation v^2=-11v ?
The solutions to the equation v^2=-11v are v=0,v=-11
Find the zeros of v^2=-11v
The zeros of v^2=-11v are v=0,v=-11