What are the solutions to the equation 4=5x^2 ?

The solutions to the equation 4=5x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

Find the zeros of 4=5x^2

The zeros of 4=5x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

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4 = 5 x^{2}

x = \frac{2}{5}, x = - \frac{2}{5}

Decimal Notation

x = 0.89442 \dots, x = - 0.89442 \dots

Solution steps

4 = 5 x^{2}

Switch sides

5 x^{2} = 4

Divide both sides by

5

x^{2} = \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{5}, x = - \frac{4}{5}

\frac{4}{5} = \frac{2}{5}

- \frac{4}{5} = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

x, T = \frac{x ^{2} - y ^{2}}{z ^{2}}

10 y^{2} = 1 - 3 y

y^{2} = 2 y + 3

3 x (x - 2) - (x + 3) = 23 (x - 3)

x^{2} = 21 - 4 x

What are the solutions to the equation 4=5x^2 ?
The solutions to the equation 4=5x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))
Find the zeros of 4=5x^2
The zeros of 4=5x^2 are x= 2/(sqrt(5)),x=-2/(sqrt(5))