What are the solutions to the equation x^2+100x+250=0 ?

The solutions to the equation x^2+100x+250=0 are x=5(3sqrt(10)-10),x=-5(10+3sqrt(10))

Find the zeros of x^2+100x+250=0

The zeros of x^2+100x+250=0 are x=5(3sqrt(10)-10),x=-5(10+3sqrt(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 100 x + 250 = 0

x = 5 (310 - 10), x = - 5 (10 + 310)

Decimal Notation

x = - 2.56583 \dots, x = - 97.43416 \dots

Solution steps

x^{2} + 100 x + 250 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 1 \cdot 250}{2 \cdot 1}

10 0^{2} - 4 \cdot 1 \cdot 250 = 3010

x_{1, 2} = \frac{- 100 \pm 30 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 100 + 30 10}{2 \cdot 1}, x_{2} = \frac{- 100 - 30 10}{2 \cdot 1}

x = \frac{- 100 + 30 10}{2 \cdot 1} : 5 (310 - 10)

x = \frac{- 100 - 30 10}{2 \cdot 1} : - 5 (10 + 310)

The solutions to the quadratic equation are:

x = 5 (310 - 10), x = - 5 (10 + 310)

x^{2} - 3 x - 2 = 0

- 2 x = - x^{2}

(4 x - 1) (x + 2) = 4 x

3 x^{2} + 6 (x - 5) = 8 (2 x - 7)

x^{2} - 7 x + 40 = 0

What are the solutions to the equation x^2+100x+250=0 ?
The solutions to the equation x^2+100x+250=0 are x=5(3sqrt(10)-10),x=-5(10+3sqrt(10))
Find the zeros of x^2+100x+250=0
The zeros of x^2+100x+250=0 are x=5(3sqrt(10)-10),x=-5(10+3sqrt(10))