What are the solutions to the equation 40t-5t^2=75 ?

The solutions to the equation 40t-5t^2=75 are t=3,t=5

Find the zeros of 40t-5t^2=75

The zeros of 40t-5t^2=75 are t=3,t=5

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40 t - 5 t^{2} = 75

t = 3, t = 5

Solution steps

40 t - 5 t^{2} = 75

Move

75

to the left side

40 t - 5 t^{2} - 75 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 t^{2} + 40 t - 75 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 5 ) ( - 75 )}{2 ( - 5 )}

4 0^{2} - 4 (- 5) (- 75) = 10

t_{1, 2} = \frac{- 40 \pm 10}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- 40 + 10}{2 ( - 5 )}, t_{2} = \frac{- 40 - 10}{2 ( - 5 )}

t = \frac{- 40 + 10}{2 ( - 5 )} : 3

t = \frac{- 40 - 10}{2 ( - 5 )} : 5

The solutions to the quadratic equation are:

t = 3, t = 5

c (x) = \frac{1}{4} x^{2} + 4 x + 100

4 x^{2} + 20 x - 11 = 0

y, y^{2} = x^{3} - 3 x + 1

- 6 x^{2} + 96 x = 0

- 6 n^{2} + 15 n = 0

What are the solutions to the equation 40t-5t^2=75 ?
The solutions to the equation 40t-5t^2=75 are t=3,t=5
Find the zeros of 40t-5t^2=75
The zeros of 40t-5t^2=75 are t=3,t=5