What are the solutions to the equation 12x^2-3=5x ?

The solutions to the equation 12x^2-3=5x are x= 3/4 ,x=-1/3

Find the zeros of 12x^2-3=5x

The zeros of 12x^2-3=5x are x= 3/4 ,x=-1/3

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12 x^{2} - 3 = 5 x

x = \frac{3}{4}, x = - \frac{1}{3}

Decimal Notation

x = 0.75, x = - 0.33333 \dots

Solution steps

12 x^{2} - 3 = 5 x

Move

5 x

to the left side

12 x^{2} - 3 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 12 ( - 3 )}{2 \cdot 12}

(- 5)^{2} - 4 \cdot 12 (- 3) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 12}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 12}

x = \frac{- ( - 5 ) + 13}{2 \cdot 12} : \frac{3}{4}

x = \frac{- ( - 5 ) - 13}{2 \cdot 12} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{1}{3}

- 4 x^{2} + 2 x - 1 = 0

225 z^{2} + 450 z

(x + 6)^{2} = - 100

x, w = \frac{( x ^{2} - y ^{2} )}{( y ^{2} + z ^{2} )}

x, x^{2} y = (y + 1)^{2}

What are the solutions to the equation 12x^2-3=5x ?
The solutions to the equation 12x^2-3=5x are x= 3/4 ,x=-1/3
Find the zeros of 12x^2-3=5x
The zeros of 12x^2-3=5x are x= 3/4 ,x=-1/3