What are the solutions to the equation (2X-1)^2=8 ?

The solutions to the equation (2X-1)^2=8 are X=(2sqrt(2)+1)/2 ,X=(-2sqrt(2)+1)/2

Find the zeros of (2X-1)^2=8

The zeros of (2X-1)^2=8 are X=(2sqrt(2)+1)/2 ,X=(-2sqrt(2)+1)/2

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(2 X - 1)^{2} = 8

X = \frac{2 2 + 1}{2}, X = \frac{- 2 2 + 1}{2}

Decimal Notation

X = 1.91421 \dots, X = - 0.91421 \dots

Solution steps

(2 X - 1)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 X - 1 = 8 : X = \frac{2 2 + 1}{2}

Solve

2 X - 1 = - 8 : X = \frac{- 2 2 + 1}{2}

The solutions to the quadratic equation are:

X = \frac{2 2 + 1}{2}, X = \frac{- 2 2 + 1}{2}

2 x^{2} + 12 x = - 5

a x^{2} + 2 a = x + 2 a^{2} x

x = - 2 x^{2} - (b - 8) x + \frac{b}{3}

x^{2} - 49 = 0

\frac{x ^{2}}{25} = 16

What are the solutions to the equation (2X-1)^2=8 ?
The solutions to the equation (2X-1)^2=8 are X=(2sqrt(2)+1)/2 ,X=(-2sqrt(2)+1)/2
Find the zeros of (2X-1)^2=8
The zeros of (2X-1)^2=8 are X=(2sqrt(2)+1)/2 ,X=(-2sqrt(2)+1)/2