What are the solutions to the equation s^2=-14-3s ?

The solutions to the equation s^2=-14-3s are s=-3/2+i(sqrt(47))/2 ,s=-3/2-i(sqrt(47))/2

Find the zeros of s^2=-14-3s

The zeros of s^2=-14-3s are s=-3/2+i(sqrt(47))/2 ,s=-3/2-i(sqrt(47))/2

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s^{2} = - 14 - 3 s

s = - \frac{3}{2} + i \frac{47}{2}, s = - \frac{3}{2} - i \frac{47}{2}

Solution steps

s^{2} = - 14 - 3 s

Move

3 s

to the left side

s^{2} + 3 s = - 14

Move

14

to the left side

s^{2} + 3 s + 14 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 14 : 47 i

s_{1, 2} = \frac{- 3 \pm 47 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 3 + 47 i}{2 \cdot 1}, s_{2} = \frac{- 3 - 47 i}{2 \cdot 1}

s = \frac{- 3 + 47 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{47}{2}

s = \frac{- 3 - 47 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{47}{2}

The solutions to the quadratic equation are:

s = - \frac{3}{2} + i \frac{47}{2}, s = - \frac{3}{2} - i \frac{47}{2}

x, x^{2} y = 4 x^{2} + 7 x y + 2 y^{2}

\frac{1}{2} x^{2} + 1 = 2 x - 1

5 x^{2} = 51 + 2

4 y^{2} - 28 = 8 y

9^{2} = 6^{2} + x^{2}

What are the solutions to the equation s^2=-14-3s ?
The solutions to the equation s^2=-14-3s are s=-3/2+i(sqrt(47))/2 ,s=-3/2-i(sqrt(47))/2
Find the zeros of s^2=-14-3s
The zeros of s^2=-14-3s are s=-3/2+i(sqrt(47))/2 ,s=-3/2-i(sqrt(47))/2