What are the solutions to the equation 5p^2+19p+12=0 ?

The solutions to the equation 5p^2+19p+12=0 are p=-4/5 ,p=-3

Find the zeros of 5p^2+19p+12=0

The zeros of 5p^2+19p+12=0 are p=-4/5 ,p=-3

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5 p^{2} + 19 p + 12 = 0

p = - \frac{4}{5}, p = - 3

Decimal Notation

p = - 0.8, p = - 3

Solution steps

5 p^{2} + 19 p + 12 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

1 9^{2} - 4 \cdot 5 \cdot 12 = 11

p_{1, 2} = \frac{- 19 \pm 11}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- 19 + 11}{2 \cdot 5}, p_{2} = \frac{- 19 - 11}{2 \cdot 5}

p = \frac{- 19 + 11}{2 \cdot 5} : - \frac{4}{5}

p = \frac{- 19 - 11}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

p = - \frac{4}{5}, p = - 3

(2 x + 3) (3 x - 4) = - 5

6 y^{2} = 19 y - 15

x, x^{2} y - 4 x = 5

a (a + 24) = 0

4 x^{2} + 20 x + 25

What are the solutions to the equation 5p^2+19p+12=0 ?
The solutions to the equation 5p^2+19p+12=0 are p=-4/5 ,p=-3
Find the zeros of 5p^2+19p+12=0
The zeros of 5p^2+19p+12=0 are p=-4/5 ,p=-3