What are the solutions to the equation 132x-12x^2=0 ?

The solutions to the equation 132x-12x^2=0 are x=0,x=11

Find the zeros of 132x-12x^2=0

The zeros of 132x-12x^2=0 are x=0,x=11

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132 x - 12 x^{2} = 0

x = 0, x = 11

Solution steps

132 x - 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 12 x^{2} + 132 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 132 \pm 13 2 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

13 2^{2} - 4 (- 12) \cdot 0 = 132

x_{1, 2} = \frac{- 132 \pm 132}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 132 + 132}{2 ( - 12 )}, x_{2} = \frac{- 132 - 132}{2 ( - 12 )}

x = \frac{- 132 + 132}{2 ( - 12 )} : 0

x = \frac{- 132 - 132}{2 ( - 12 )} : 11

The solutions to the quadratic equation are:

x = 0, x = 11

x, x^{2} + y^{2} - 4 x + 2 y + 36 = 0

b, b^{2} + d^{2} = 14 b d

x, 36 x^{2} + 100 y^{2} - 72 x + 200 y + 3464 = 0

2 x^{2} = 15

2 x^{2} = 60

What are the solutions to the equation 132x-12x^2=0 ?
The solutions to the equation 132x-12x^2=0 are x=0,x=11
Find the zeros of 132x-12x^2=0
The zeros of 132x-12x^2=0 are x=0,x=11