What are the solutions to the equation solvefor y,y^2=x(x-4)^2 ?

The solutions to the equation solvefor y,y^2=x(x-4)^2 are y=(x-4)sqrt(x),y=-(x-4)sqrt(x)

Find the zeros of solvefor y,y^2=x(x-4)^2

The zeros of solvefor y,y^2=x(x-4)^2 are y=(x-4)sqrt(x),y=-(x-4)sqrt(x)

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solve for

y, y^{2} = x (x - 4)^{2}

y = (x - 4) x, y = - (x - 4) x

Solution steps

y^{2} = x (x - 4)^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x (x - 4)^{2}, y = - x (x - 4)^{2}

Simplify

x (x - 4)^{2} : (x - 4) x

Simplify

- x (x - 4)^{2} : - (x - 4) x

y = (x - 4) x, y = - (x - 4) x

7 x^{2} + 6 = 17 x - 5 x^{2}

12 x^{2} - 24 x + 5 = 0

6 = 4 x - 5 x^{2}

a, an = 2 n^{2} - 1

20 - x = \frac{1}{324} x^{2} + 1

What are the solutions to the equation solvefor y,y^2=x(x-4)^2 ?
The solutions to the equation solvefor y,y^2=x(x-4)^2 are y=(x-4)sqrt(x),y=-(x-4)sqrt(x)
Find the zeros of solvefor y,y^2=x(x-4)^2
The zeros of solvefor y,y^2=x(x-4)^2 are y=(x-4)sqrt(x),y=-(x-4)sqrt(x)