What are the solutions to the equation (3x+4)^2-36=15x+20 ?

The solutions to the equation (3x+4)^2-36=15x+20 are x= 5/3 ,x=-8/3

Find the zeros of (3x+4)^2-36=15x+20

The zeros of (3x+4)^2-36=15x+20 are x= 5/3 ,x=-8/3

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(3 x + 4)^{2} - 36 = 15 x + 20

x = \frac{5}{3}, x = - \frac{8}{3}

Decimal Notation

x = 1.66666 \dots, x = - 2.66666 \dots

Solution steps

(3 x + 4)^{2} - 36 = 15 x + 20

Expand

(3 x + 4)^{2} - 36 : 9 x^{2} + 24 x - 20

9 x^{2} + 24 x - 20 = 15 x + 20

Move

20

to the left side

9 x^{2} + 24 x - 40 = 15 x

Move

15 x

to the left side

9 x^{2} + 9 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 9 ( - 40 )}{2 \cdot 9}

9^{2} - 4 \cdot 9 (- 40) = 39

x_{1, 2} = \frac{- 9 \pm 39}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 9 + 39}{2 \cdot 9}, x_{2} = \frac{- 9 - 39}{2 \cdot 9}

x = \frac{- 9 + 39}{2 \cdot 9} : \frac{5}{3}

x = \frac{- 9 - 39}{2 \cdot 9} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - \frac{8}{3}

2 x^{2} - 14 - x = - x^{2}

9 x^{2} - 2 x = 7

x, 12 x^{2} - 16 = 0

2 x^{2} + x = 8

\frac{1}{2} x^{2} - 3 x + 5 = 0

What are the solutions to the equation (3x+4)^2-36=15x+20 ?
The solutions to the equation (3x+4)^2-36=15x+20 are x= 5/3 ,x=-8/3
Find the zeros of (3x+4)^2-36=15x+20
The zeros of (3x+4)^2-36=15x+20 are x= 5/3 ,x=-8/3