What are the solutions to the equation (x^2+1)=0 ?

The solutions to the equation (x^2+1)=0 are x=i,x=-i

Find the zeros of (x^2+1)=0

The zeros of (x^2+1)=0 are x=i,x=-i

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(x^{2} + 1) = 0

x = i, x = - i

Solution steps

(x^{2} + 1) = 0

x^{2} + 1 = 0

Move

1

to the right side

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

3 - 4 x + 2 = 13

\frac{1}{4} (4 + x) = \frac{4}{3}

8 x - 3 > 1

\frac{m ^{2} - 7 m - 18}{m ^{2} - 10 m + 9} + \frac{6}{m - 1}

- 42 a^{4} b^{3} + 36 a^{3} b^{4} + 18 a^{4} b^{4}

What are the solutions to the equation (x^2+1)=0 ?
The solutions to the equation (x^2+1)=0 are x=i,x=-i
Find the zeros of (x^2+1)=0
The zeros of (x^2+1)=0 are x=i,x=-i